(5x^2-4)^1/4=x

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Solution for (5x^2-4)^1/4=x equation: 



(5x^2-4)^1/4=x

We move all terms to the left:

(5x^2-4)^1/4-(x)=0

We add all the numbers together, and all the variables

-1x+(5x^2-4)^1/4=0

We multiply all the terms by the denominator


-1x*4+(5x^2-4)^1=0

Wy multiply elements

-4x+(5x^2-4)^1=0

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